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18x^2-57x-21=0
a = 18; b = -57; c = -21;
Δ = b2-4ac
Δ = -572-4·18·(-21)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-69}{2*18}=\frac{-12}{36} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+69}{2*18}=\frac{126}{36} =3+1/2 $
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